Integrand size = 21, antiderivative size = 378 \[ \int x^m \left (d+e x^2\right )^3 (a+b \arctan (c x)) \, dx=-\frac {b e \left (e^2 \left (15+8 m+m^2\right )-3 c^2 d e \left (21+10 m+m^2\right )+3 c^4 d^2 \left (35+12 m+m^2\right )\right ) x^{2+m}}{c^5 (2+m) (3+m) (5+m) (7+m)}+\frac {b e^2 \left (e (5+m)-3 c^2 d (7+m)\right ) x^{4+m}}{c^3 (4+m) (5+m) (7+m)}-\frac {b e^3 x^{6+m}}{c (6+m) (7+m)}+\frac {d^3 x^{1+m} (a+b \arctan (c x))}{1+m}+\frac {3 d^2 e x^{3+m} (a+b \arctan (c x))}{3+m}+\frac {3 d e^2 x^{5+m} (a+b \arctan (c x))}{5+m}+\frac {e^3 x^{7+m} (a+b \arctan (c x))}{7+m}+\frac {b \left (e^3 \left (15+23 m+9 m^2+m^3\right )-3 c^2 d e^2 \left (21+31 m+11 m^2+m^3\right )+3 c^4 d^2 e \left (35+47 m+13 m^2+m^3\right )-c^6 d^3 \left (105+71 m+15 m^2+m^3\right )\right ) x^{2+m} \operatorname {Hypergeometric2F1}\left (1,\frac {2+m}{2},\frac {4+m}{2},-c^2 x^2\right )}{c^5 (1+m) (2+m) (3+m) (5+m) (7+m)} \]
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Time = 1.33 (sec) , antiderivative size = 374, normalized size of antiderivative = 0.99, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.190, Rules used = {276, 5096, 1816, 371} \[ \int x^m \left (d+e x^2\right )^3 (a+b \arctan (c x)) \, dx=\frac {d^3 x^{m+1} (a+b \arctan (c x))}{m+1}+\frac {3 d^2 e x^{m+3} (a+b \arctan (c x))}{m+3}+\frac {3 d e^2 x^{m+5} (a+b \arctan (c x))}{m+5}+\frac {e^3 x^{m+7} (a+b \arctan (c x))}{m+7}-\frac {b e^2 x^{m+4} \left (\frac {3 c^2 d}{m+5}-\frac {e}{m+7}\right )}{c^3 (m+4)}-\frac {b e x^{m+2} \left (3 c^4 d^2 \left (m^2+12 m+35\right )-3 c^2 d e \left (m^2+10 m+21\right )+e^2 \left (m^2+8 m+15\right )\right )}{c^5 (m+2) (m+3) (m+5) (m+7)}+\frac {b x^{m+2} \left (c^6 \left (-d^3\right ) \left (m^3+15 m^2+71 m+105\right )+3 c^4 d^2 e \left (m^3+13 m^2+47 m+35\right )-3 c^2 d e^2 \left (m^3+11 m^2+31 m+21\right )+e^3 \left (m^3+9 m^2+23 m+15\right )\right ) \operatorname {Hypergeometric2F1}\left (1,\frac {m+2}{2},\frac {m+4}{2},-c^2 x^2\right )}{c^5 (m+1) (m+2) (m+3) (m+5) (m+7)}-\frac {b e^3 x^{m+6}}{c (m+6) (m+7)} \]
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Rule 276
Rule 371
Rule 1816
Rule 5096
Rubi steps \begin{align*} \text {integral}& = \frac {d^3 x^{1+m} (a+b \arctan (c x))}{1+m}+\frac {3 d^2 e x^{3+m} (a+b \arctan (c x))}{3+m}+\frac {3 d e^2 x^{5+m} (a+b \arctan (c x))}{5+m}+\frac {e^3 x^{7+m} (a+b \arctan (c x))}{7+m}-(b c) \int \frac {x^{1+m} \left (\frac {d^3}{1+m}+\frac {3 d^2 e x^2}{3+m}+\frac {3 d e^2 x^4}{5+m}+\frac {e^3 x^6}{7+m}\right )}{1+c^2 x^2} \, dx \\ & = \frac {d^3 x^{1+m} (a+b \arctan (c x))}{1+m}+\frac {3 d^2 e x^{3+m} (a+b \arctan (c x))}{3+m}+\frac {3 d e^2 x^{5+m} (a+b \arctan (c x))}{5+m}+\frac {e^3 x^{7+m} (a+b \arctan (c x))}{7+m}-(b c) \int \left (\frac {e \left (e^2 \left (15+8 m+m^2\right )-3 c^2 d e \left (21+10 m+m^2\right )+3 c^4 d^2 \left (35+12 m+m^2\right )\right ) x^{1+m}}{c^6 (3+m) (5+m) (7+m)}+\frac {e^2 \left (\frac {3 c^2 d}{5+m}-\frac {e}{7+m}\right ) x^{3+m}}{c^4}+\frac {e^3 x^{5+m}}{c^2 (7+m)}+\frac {\left (105 c^6 d^3-105 c^4 d^2 e+63 c^2 d e^2-15 e^3+71 c^6 d^3 m-141 c^4 d^2 e m+93 c^2 d e^2 m-23 e^3 m+15 c^6 d^3 m^2-39 c^4 d^2 e m^2+33 c^2 d e^2 m^2-9 e^3 m^2+c^6 d^3 m^3-3 c^4 d^2 e m^3+3 c^2 d e^2 m^3-e^3 m^3\right ) x^{1+m}}{c^6 (1+m) (3+m) (5+m) (7+m) \left (1+c^2 x^2\right )}\right ) \, dx \\ & = -\frac {b e \left (e^2 \left (15+8 m+m^2\right )-3 c^2 d e \left (21+10 m+m^2\right )+3 c^4 d^2 \left (35+12 m+m^2\right )\right ) x^{2+m}}{c^5 (2+m) (3+m) (5+m) (7+m)}-\frac {b e^2 \left (\frac {3 c^2 d}{5+m}-\frac {e}{7+m}\right ) x^{4+m}}{c^3 (4+m)}-\frac {b e^3 x^{6+m}}{c (6+m) (7+m)}+\frac {d^3 x^{1+m} (a+b \arctan (c x))}{1+m}+\frac {3 d^2 e x^{3+m} (a+b \arctan (c x))}{3+m}+\frac {3 d e^2 x^{5+m} (a+b \arctan (c x))}{5+m}+\frac {e^3 x^{7+m} (a+b \arctan (c x))}{7+m}+\frac {\left (b \left (e^3 \left (15+23 m+9 m^2+m^3\right )-3 c^2 d e^2 \left (21+31 m+11 m^2+m^3\right )+3 c^4 d^2 e \left (35+47 m+13 m^2+m^3\right )-c^6 d^3 \left (105+71 m+15 m^2+m^3\right )\right )\right ) \int \frac {x^{1+m}}{1+c^2 x^2} \, dx}{c^5 (1+m) (3+m) (5+m) (7+m)} \\ & = -\frac {b e \left (e^2 \left (15+8 m+m^2\right )-3 c^2 d e \left (21+10 m+m^2\right )+3 c^4 d^2 \left (35+12 m+m^2\right )\right ) x^{2+m}}{c^5 (2+m) (3+m) (5+m) (7+m)}-\frac {b e^2 \left (\frac {3 c^2 d}{5+m}-\frac {e}{7+m}\right ) x^{4+m}}{c^3 (4+m)}-\frac {b e^3 x^{6+m}}{c (6+m) (7+m)}+\frac {d^3 x^{1+m} (a+b \arctan (c x))}{1+m}+\frac {3 d^2 e x^{3+m} (a+b \arctan (c x))}{3+m}+\frac {3 d e^2 x^{5+m} (a+b \arctan (c x))}{5+m}+\frac {e^3 x^{7+m} (a+b \arctan (c x))}{7+m}+\frac {b \left (e^3 \left (15+23 m+9 m^2+m^3\right )-3 c^2 d e^2 \left (21+31 m+11 m^2+m^3\right )+3 c^4 d^2 e \left (35+47 m+13 m^2+m^3\right )-c^6 d^3 \left (105+71 m+15 m^2+m^3\right )\right ) x^{2+m} \operatorname {Hypergeometric2F1}\left (1,\frac {2+m}{2},\frac {4+m}{2},-c^2 x^2\right )}{c^5 (1+m) (2+m) (3+m) (5+m) (7+m)} \\ \end{align*}
Time = 0.40 (sec) , antiderivative size = 264, normalized size of antiderivative = 0.70 \[ \int x^m \left (d+e x^2\right )^3 (a+b \arctan (c x)) \, dx=x^{1+m} \left (\frac {d^3 (a+b \arctan (c x))}{1+m}+\frac {3 d^2 e x^2 (a+b \arctan (c x))}{3+m}+\frac {3 d e^2 x^4 (a+b \arctan (c x))}{5+m}+\frac {e^3 x^6 (a+b \arctan (c x))}{7+m}-\frac {b c e^3 x^7 \operatorname {Hypergeometric2F1}\left (1,4+\frac {m}{2},5+\frac {m}{2},-c^2 x^2\right )}{(7+m) (8+m)}-\frac {b c d^3 x \operatorname {Hypergeometric2F1}\left (1,\frac {2+m}{2},\frac {4+m}{2},-c^2 x^2\right )}{2+3 m+m^2}-\frac {3 b c d^2 e x^3 \operatorname {Hypergeometric2F1}\left (1,\frac {4+m}{2},\frac {6+m}{2},-c^2 x^2\right )}{12+7 m+m^2}-\frac {3 b c d e^2 x^5 \operatorname {Hypergeometric2F1}\left (1,\frac {6+m}{2},\frac {8+m}{2},-c^2 x^2\right )}{(5+m) (6+m)}\right ) \]
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\[\int x^{m} \left (e \,x^{2}+d \right )^{3} \left (a +b \arctan \left (c x \right )\right )d x\]
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\[ \int x^m \left (d+e x^2\right )^3 (a+b \arctan (c x)) \, dx=\int { {\left (e x^{2} + d\right )}^{3} {\left (b \arctan \left (c x\right ) + a\right )} x^{m} \,d x } \]
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\[ \int x^m \left (d+e x^2\right )^3 (a+b \arctan (c x)) \, dx=\int x^{m} \left (a + b \operatorname {atan}{\left (c x \right )}\right ) \left (d + e x^{2}\right )^{3}\, dx \]
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\[ \int x^m \left (d+e x^2\right )^3 (a+b \arctan (c x)) \, dx=\int { {\left (e x^{2} + d\right )}^{3} {\left (b \arctan \left (c x\right ) + a\right )} x^{m} \,d x } \]
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\[ \int x^m \left (d+e x^2\right )^3 (a+b \arctan (c x)) \, dx=\int { {\left (e x^{2} + d\right )}^{3} {\left (b \arctan \left (c x\right ) + a\right )} x^{m} \,d x } \]
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Timed out. \[ \int x^m \left (d+e x^2\right )^3 (a+b \arctan (c x)) \, dx=\int x^m\,\left (a+b\,\mathrm {atan}\left (c\,x\right )\right )\,{\left (e\,x^2+d\right )}^3 \,d x \]
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